2x^2-48=20x

Solution for 2x^2-48=20x equation:

2x^2-48=20x

We move all terms to the left:

2x^2-48-(20x)=0

a = 2; b = -20; c = -48;
Δ = b2-4ac
Δ = -202-4·2·(-48)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-28}{2*2}=\frac{-8}{4}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+28}{2*2}=\frac{48}{4}
=12
$